How do I find the lim x → 0 7 x 3 − 4 x 2 sin ⁡ ( 3 x 2 ) without using L’Hopital’s?

Question

How do I find the       lim          x      →      0                  7              x        3            −      4              x        2                    sin      ⁡      (      3              x        2            )       without using L’Hopital’s?

Leah Conley · Accepted Answer

lim                      x            →            0                                                7                          x              3                        −            4                          x              2                                            sin            ⁡            (            3                          x              2                        )                                              =                  lim                      x            →            0                                                7            x            −            4                    3                ⋅                  lim                      x            →            0                                                3                          x              2                                            sin            ⁡            (            3                          x              2                        )                                                            =        −                  4          3                ⋅        1                                          =        −                  4          3

How do I find the <munder> <mo movablelimits="true" form="prefix">lim <mrow class="MJX

Answered question

Answer & Explanation

New Questions in Differential Calculus