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Kapalci

Kapalci

Answered question

2022-06-20

Evaluate lim x π ( sin x π 2 x 2 ) without L'Hopital or Taylor series

Answer & Explanation

Bruno Hughes

Bruno Hughes

Beginner2022-06-21Added 24 answers

hint: sin x = sin ( π x ), and π 2 x 2 = ( π x ) ( π + x )
Also use sin ( π x ) π x 1 when x π

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