The question is: lim x → 0 + x 1 / x .

Let t = 1 x . When x → 0 + is going to + ∞. So, the limit is going to become: lim t → + ∞ ( 1 t ) t = lim t → + ∞ e − ln ⁡ ( t ) ⋅ t = 0 a b = e ln ⁡ ( a ) ⋅ b

Get the answer to "The question is: lim x → 0 +..."

Frederick Kramer

Answered question

2022-07-04

The question is:

lim_{x \to 0^{+}} x^{1 / x} .

Answer & Explanation

Hayley Mccarthy

Beginner2022-07-05Added 19 answers

Let

t = \frac{1}{x}

. When

x \to 0^{+}

is going to

+ \infty

. So, the limit is going to become:

lim_{t \to + \infty} {(\frac{1}{t})}^{t} = lim_{t \to + \infty} e^{- \ln (t) \cdot t} = 0

a^{b} = e^{\ln (a) \cdot b}

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Differential Calculus

What is the Mixed Derivative Theorem for mixed second-order partial derivatives? How can it help in calculating partial derivatives of second and higher orders?
How do I find the y-intercept of a parabola?
What are the vertices of $9 x^{2} + 16 y^{2} = 144$ ?
How to determine the rate of change of a function?
Why are the tangents for 90 and 270 degrees undefined?
How to find the center and radius of the circle $x^{2} + y^{2} - 6 x + 8 y = 0$ ?
What is multiplicative inverse of a number?
How to find the continuity of a function on a closed interval?
How do I find the tangent line of a function?
How to find vertical asymptotes using limits?
How to find the center and radius of the circle $x^{2} - 12 x + y^{2} + 4 y + 15 = 0$ ?
Let f be a function so that (below). Which must be true?
I. f is continuous at x=2
II. f is differentiable at x=2
III. The derivative of f is continuous at x=2
(A) I (B) II (C) I and II (D) I and III (E) II and III
How to find the center and radius of the circle given $x^{2} + y^{2} + 8 x - 6 y = 0$ ?
How to find the center and radius of the circle $x^{2} + y^{2} + 4 x - 8 y + 4 = 0$ ?
How to identify the center and radius of the circle ${(x + 3)}^{2} + {(y - 8)}^{2} = 16$ ?

Didn't find what you were looking for?