Finding lim_(n => infty) (sqrt(n!))/(2^n)

embelurildmixjm

embelurildmixjm

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2022-08-22

Finding lim n n ! 2 n

Answer & Explanation

Katrina Fisher

Katrina Fisher

Beginner2022-08-23Added 3 answers

n ! 2 n ( 2 π n ) 1 / 4 ( n e ) n / 2 2 n = ( 2 π n ) 1 / 4 ( n 2 e ) n .
Since n 2 e and n 1 / 4 converge to , so does n ! 2 n

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