AA epsilon>0,EEdelta in R,AAx in R(|x−c|<delta=>|f(x)−f(c)|<epsilon) is false?

robbbiehu

robbbiehu

Answered question

2022-10-21

Let the function f : R R be discontinuous at c. Then the statement: ϵ > 0 , δ R , x R ( | x c | < δ | f ( x ) f ( c ) | < ϵ ) is false. The negation of the statement: ϵ > 0 , δ R , x R ( | x c | < δ a n d | f ( x ) f ( c ) | ϵ ) is false because whenever δ is negative, | x c | < δ is false. Is anything wrong here? Thank you!

Answer & Explanation

dkmc4175fl

dkmc4175fl

Beginner2022-10-22Added 15 answers

Your initial comment was intended to convey "continuity at c", but it's not written precisely enough! In fact, the original statement you gave is true, because you can pick δ = 0, regardless of the value of ϵ.
The amended version of the original statement is as follows:
 ϵ > 0   δ > 0   x  R ( | x  c | < δ    | f ( x )  f ( c ) | < ϵ )
This statement is actually false (by definition), assuming that f is not continuous at c. The negation is
 ϵ > 0   δ > 0   x  R ( | x  c | < δ   and   | f ( x )  f ( c ) |  ϵ )
Really, this is accurate.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?