A plane autonomous system where there exists two ODEs, dx/dt=X(x,y),dy/dt=Y(x,y). We then usually draw trajectories on the phase plane to indicate the solutions on the plane. If a trajectory does contain a critical point, wouldn't this trajectory just stay at that critical point rather than passing through that critical point since at that point X=Y=0 and so just becomes stationary?

klesstilne1

klesstilne1

Answered question

2022-11-02

A plane autonomous system where there exists two ODEs, d x d t = X ( x , y ) , d y d t = Y ( x , y ). We then usually draw trajectories on the phase plane to indicate the solutions on the plane.
If a trajectory does contain a critical point, wouldn't this trajectory just stay at that critical point rather than passing through that critical point since at that point X = Y = 0 and so just becomes stationary?

Answer & Explanation

kuthiwenihca

kuthiwenihca

Beginner2022-11-03Added 23 answers

The simplest example is
d x d t = x , d y d t = y   .
When r ( 0 ) = ( x 0 , 0 ), x 0 0, then
r ( t ) = ( 0 , y 0 e t ) ( < t < )   ,
hence the half y-axis containing y 0 is a solution curve. But note that this curve reaches ( 0 , 0 ) only in the limit t . This means that the traveling point needs infinite time to reach the origin. And of course the initial condition t leads to r ( t ) = ( 0 , 0 ) for all r ( t ) = ( 0 , 0 ).
Therefore no trajectory "traverses" the stationary point ( 0 , 0 ).

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