Find out the answer to "The electrical resistivity of silver is 1.60×10-6Ωm. What..."

markezop78

Answered question

2023-02-02

The electrical resistivity of silver is

1.60 \times 10^{- 6} Ω m

. What will be the resistance of a silver wire of length

10 m

and cross-sectional area

2 \times 10^{- 3} m^{2}

Dwayne Herring

Beginner2023-02-03Added 4 answers

Step 1- Given data and formula
Length of the silver wire

l = 10 m

Area of cross-section

A = 2 \times 10^{- 3} m^{2}

Resistivity of silver

ρ = 1.60 \times 10^{- 6} Ω m

The formula for resistance

R

R = ρ \frac{l}{A}

Step 2- Finding the resistance of the silver wire
Substitute the values into the above formula to calculate

R

R = (1.60 \times 10^{- 6} Ω m) \times \frac{(10 m)}{(2 \times 10^{- 3} m^{2})} R = 8 \times 10^{- 3} Ω

Consequently, the silver wire's resistance is

8 \times 10^{- 3} Ω

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