facas9
2020-12-16
Two resistors, A and B, are connected in parallel across a 6.0V battery. The current through B is found to be 2.0 A. When the two resistos are connected in series to the 6.0 V battery,a voltmeter connected across the resistor A measures a voltage of4.0 V. Find the resistances of A and B.
Laaibah Pitt
Skilled2020-12-17Added 98 answers
When the resistors are in series the voltage drop across B is 6V - 4V = 2V
When the resistors are in parallel the voltage is the same across both A and B. Therefore you have the current andthe voltage across B and can us Ohm's Law to find the resistance.
Now jumping back to the series circuit you now have the resistance of B you can find the current using Ohm's Law
and since current is the same in for all resistances in a series circuit this is the same current through A And B.
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