A circuit with a resistance of <mn>6</mn>

kulisamilhh

kulisamilhh

Answered question

2022-04-25

A circuit with a resistance of 6 Ω has a fuse that melts at 8A. Can a voltage of 42V be applied to the circuit without blowing the fuse?

Answer & Explanation

Dashawn Robbins

Dashawn Robbins

Beginner2022-04-25Added 1 answers

First, we need to find the voltage at which the fuse melts.
Thus, we use Ohm's law here, which states that
V=IR
The fuse melts at 8A with a resistance of 6 Ω , so we must plug in those values into the equation.
We get:
V = 8 A 6 Ω
=48V
So, the fuse will melt at 48V or more.
Since 42V < 48V, then the fuse will not melt when a voltage of 42 volts is passed through it.
So, a voltage of 42V can be applied on the circuit without blowing the fuse.

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