When a 120 V potential difference is applied across a

lifretatox8n

lifretatox8n

Answered question

2022-05-10

When a 120 V potential difference is applied across a 30 Ω resistance of electric device. What is the current through the electric device? What is the power of the electric device?

Answer & Explanation

odvucimo1pp17

odvucimo1pp17

Beginner2022-05-11Added 23 answers

Apply Ohm's Law
voltage = Resistance × Current
U=RI
The voltage is U=120V
The resistance is R = 30 Ω
The current is
I = U R = 120 30 = 4 A
The power is
P=UI=120*4=480W
Stoyanovahvsbh

Stoyanovahvsbh

Beginner2022-05-12Added 3 answers

We first find the current flowing through the device using Ohm's law, which is:
V=IR
I is the current in amperes
R is the resistance in ohms
And so,
120 V = I 30 Ω
I = 120 V 30 Ω
=4A
To find the power, we use the equation,
P=IV
So, the power here is:
P=4A*120V
=480W

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