What is the minimal polynomial of &#x03B1;<!-- α --> = 3 <mrow class=

syaoronsangelhwc17

syaoronsangelhwc17

Answered question

2022-05-14

What is the minimal polynomial of α = 3 1 / 2 1 + 2 1 / 3 over Q ?

Answer & Explanation

Mathias Patrick

Mathias Patrick

Beginner2022-05-15Added 22 answers

Since, α = 3 1 / 2 1 + 2 1 / 3 = 3 1 / 2 ( 1 2 1 / 3 + 2 2 / 3 ), let β = α 2 = 2 2 / 3 1. Then
[ β 0 β 1 β 2 β 3 ] = [ 1 0 0 1 0 1 1 2 2 3 6 3 ] [ 1 2 1 / 3 2 2 / 3 ]
With a bit of linear algebra, or perhaps inspection, it is not too difficult to see that
β 3 + 3 β 2 + 3 β 3 = 0
Therefore,
α 6 + 3 α 4 + 3 α 2 3 = 0
which is irreducible by Eisenstein's Criterion.

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