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2022-05-18

How much power is produced if a voltage of 4V is applied to a circuit with a resistance of $27\mathrm{\Omega}$ ?

Lucille Lucas

Beginner2022-05-19Added 16 answers

Probably not a lot more explanation needed. We are given a voltage (V) And a resistance ($\mathrm{\Omega}$). We know that the expression for power in a circuit is P=VI, but we don't know the current.

We do know a way to find the current, given the voltage and the resistance: Ohm's Law :

V=IR

Rearranging:

$I=\frac{V}{R}$

We could calculate the current and then substitute that into the expression for the power, but I decided to combine the equations instead:

$P=VI=V(\frac{V}{R})=\frac{{V}^{2}}{R}$

Then it's just a matter of substituting in the values we have and we know the power produced by the circuit.

We do know a way to find the current, given the voltage and the resistance: Ohm's Law :

V=IR

Rearranging:

$I=\frac{V}{R}$

We could calculate the current and then substitute that into the expression for the power, but I decided to combine the equations instead:

$P=VI=V(\frac{V}{R})=\frac{{V}^{2}}{R}$

Then it's just a matter of substituting in the values we have and we know the power produced by the circuit.

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