Mauricio Mathis

2022-07-20

Determine the resistance of metal tube in term of the external diameter D, the internal diameter d , the length l and the resistivity. Calculate the resistance of a copper tube 0.5cm thick and 2m long. The external diameter is 10cm

Ragazzonibw

Beginner2022-07-21Added 15 answers

Given:

The external diameter of tube D = 10 cm. = 0.1 m.

The thickness of the tube t = 0.5 cm = 0.005 m.

The length of the tube l = 2 m.

The resistivity of copper $\rho =1.68\text{}ohm\text{}m$

The cross section area of tube will be,

$A=\pi {D}^{2}+\pi (D-t{)}^{2}\phantom{\rule{0ex}{0ex}}A=\pi \times (0.1{)}^{2}+\pi \times (0.1-0.005{)}^{2}\phantom{\rule{0ex}{0ex}}A=0.05977\text{}{m}^{2}$

The resistance of the metal tube will be,

$R=\rho \frac{l}{A}\phantom{\rule{0ex}{0ex}}R=1.68\times 20.05977\phantom{\rule{0ex}{0ex}}R=56.215\mathrm{\Omega}$

Answer:

The resistance of the tube is $=56.215\mathrm{\Omega}$

The external diameter of tube D = 10 cm. = 0.1 m.

The thickness of the tube t = 0.5 cm = 0.005 m.

The length of the tube l = 2 m.

The resistivity of copper $\rho =1.68\text{}ohm\text{}m$

The cross section area of tube will be,

$A=\pi {D}^{2}+\pi (D-t{)}^{2}\phantom{\rule{0ex}{0ex}}A=\pi \times (0.1{)}^{2}+\pi \times (0.1-0.005{)}^{2}\phantom{\rule{0ex}{0ex}}A=0.05977\text{}{m}^{2}$

The resistance of the metal tube will be,

$R=\rho \frac{l}{A}\phantom{\rule{0ex}{0ex}}R=1.68\times 20.05977\phantom{\rule{0ex}{0ex}}R=56.215\mathrm{\Omega}$

Answer:

The resistance of the tube is $=56.215\mathrm{\Omega}$

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