Consider a resistor of resistivity 4.12 xx 10^(-8) Omega * m. If an electric field of 19 V/m is applied across the resistor and the electron volume concetration in the conductor is 5.82 xx 1028 per m3, determine the drift velocity, in mm/s, of the free electron constituting the current.

pighead73283r

pighead73283r

Answered question

2022-11-11

Consider a resistor of resistivity 4.12 × 10 8 Ω m. If an electric field of 19 V/m is applied across the resistor and the electron volume concetration in the conductor is 5.82 × 10 28 / m 3 , determine the drift velocity, in mm/s, of the free electron constituting the current.

Answer & Explanation

Frances Dodson

Frances Dodson

Beginner2022-11-12Added 17 answers

Electric field and resistivity relation is
E = ρ J
Here ρ is resistivity, E is electric field and J is current density.
The drift velocity is defined as
v d = J n e
Here J is current density, n is electron concentration and e is electric charge.
Since resistivity ρ is 4.12 × 10 8 Ω m and electric field E is 19 V/m. The current density J is
E = ρ J J = E ρ = 19   V / m 4.12 × 10 8 Ω m = 4.61 × 10 8   A / m 2
The carrier concentration n is 5.82 × 10 28 / m 3 and electric charge e is 1.6 × 10 19 C. The drift velocity v d is
v d = J n e = 4.61 × 10 8   A / m 2 ( 5.82 × 10 28 / m 3 ) ( 1.6 × 10 19   C ) = 0.05   m / s

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