The motor in a toy car operates on 6.00 V, developing a 4.50 V back emf at normal speed. If it draws 3.00 A at normal speed, what current does it draw when starting?

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revessatrP6 · Accepted Answer

Formula of current at normal speed of car is as follows:  I  =                    V        s            −              V        b              R  where,      V    s    =  source emf        V    b    =  Back emf    R  =  ResitanceCurrent drawn in circuit when it starting:      I    s    =            V      s        R  Values given in the question are as follow:      V    s    =  6     V        V    b    =  4.50  V    I  =  3.00     AResistance of circuit:Substitute known values in equation-1);  3  A  =            6      V      −      4.5      V        R      R  =  0.5Current draw in circuit of toy car in starting;Substitute known values in equation-2);      I    S    =            6      V        0.5          I    S    =  12     A

The motor in a toy car operates on 6.00 V, developing a 4.50 V back emf at normal speed. If it draws 3.00 A at normal speed, what current does it draw when starting?

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