In an electromagnetic wave, the amplitude of electric field is 1 V/m. the frequency of wave is 5 × 10 14 H z. The wave is propagating along z-axis. The average energy density of electric field, in Joulem, will be?

The formula for the electric field's average energy density is u e = 12 ϵ 0 E 2 = 12 ϵ 0 ( E 0 2 ) 2 = 14 ϵ 0 E 20 = 14 × 8.85 × 10 − 12 ( 1 ) 2 = 2.2 × 10 − 12 J / m 3

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Answered question

2023-02-09

In an electromagnetic wave, the amplitude of electric field is 1 V/m. the frequency of wave is

5 \times 10^{14} H z

. The wave is propagating along z-axis. The average energy density of electric field, in Joulem, will be?

Answer & Explanation

acropole191

Beginner2023-02-10Added 4 answers

The formula for the electric field's average energy density is

u_{e} = 12 ϵ_{0} E^{2} = 12 ϵ_{0} (E_{0} \sqrt{2})^{2} = 14 ϵ_{0} E_{20} = 14 \times 8.85 \times 10^{- 12} (1)^{2} = 2.2 \times 10^{- 12} J / m^{3}

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