The magnetic field&nbsp;B→&nbsp;in acertain region is 0.128 ,and its direction is that of the z-axis in the figure.Part AWhat is the magnetic flux across the surface abcd in the figure?Part BWhat is the magnetic flux across the surface befc ?Part C What is the magnetic flux across the surface aefd?Part DWhat is the net flux through all five surfaces that enclose the shaded volume?

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The magnetic field&amp;nbsp;B→&amp;nbsp;in acertain region is 0.128 ,and its direction is that of the z-axis in the figure.Part AWhat is the magnetic flux across the surface abcd in the figure?Part BWhat is the magnetic flux across the surface befc ?Part C What is the magnetic flux across the surface aefd?Part DWhat is the net flux through all five surfaces that enclose the shaded volume?

Faiza Fuller · Accepted Answer

a) ϕB(abcd)=B→⋅A→=0  b) ϕB(befc)=B→⋅A→=−(0.128T)(0.300 m)(0.300 m)=−0.0115Wb  c) ϕB(aefd)=B→⋅A→=BAcos⁡ϕ=35(0.128T)(0.500 m)(0.300 m)=+0.0115Wb  d) The net flux through the rest of the surface is zero since they are parallel to the x-axis so the total flux is the sum of all parts above, which is zero.

Jeffrey Jordon · Accepted Answer

Step 1  When there is a change in magnetic flux then there is induced emf in the coil and the direction of the induced emf is such that it opposes the change and its direction is given by Lenz law. The magnetic flux (ϕ) can be given by,  ϕ=BA  where,  B is the magnetic field  A is the area  Step 2  a) The magnetic flux across the surface &#039;abcd&#039; is,  ϕ=BAcos⁡θ  ϕ=0.128T×(0.4m×0.3m)×cos⁡90∘  since area vector is in negative x direction while magnetic field is in positive z direction.  ϕ=0  b) The magnitude flux across the surface &#039;befc&#039; is,  ϕ=BAcos⁡θ  ϕ=0.128T×(0.3m×0.3m)×cos⁡180∘  since area vector is in negative z direction while magnetic field is in positive z direction.  ϕ=−0.0115Wb  Step 3  c)  The magnetic flux across the surface &#039;aefd&#039; is,  The area of surface &#039;aefd&#039; is,  A=0.5×0.3=0.15m2  The angle can be calculated as,  cos⁡θ=30cm50cm  ϕ=BAcos⁡θ  ϕ=0.128T×(0.15)×35  ϕ=0.0115Wb  Step 4  d) The net flux through all five surfaces that enclose the shaded volume is given as,  ϕ=ϕabcd+ϕbefc+ϕaefd+ϕabe+ϕcdf  ϕ=0−0.0115+0.0115+0+0  ϕ=0

The magnetic field \vec{B} in acertain region is 0.128 ,and its direction is that of the z-axis in the figure.

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