A frictionless plane is 10.0 m long and inclined atA sled starts at the bottom with an initial speed of 5.00 m/s up the incline. When it reaches the point at which it momentarily stops, a second sled is released from the top of this incline with an initial speed v1 both sleds reach the bottom of thein cline at the same moment.&nbsp;(a) Determine the distance that the first sled traveled up the incline.&nbsp;(b) Determine the initial speed of the second sled.

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A frictionless plane is 10.0 m long and inclined atA sled starts at the bottom with an initial speed of 5.00 m/s up the incline. When it reaches the point at which it momentarily stops, a second sled is released from the top of this incline with an initial speed v1 both sleds reach the bottom of thein cline at the same moment.&amp;nbsp;(a) Determine the distance that the first sled traveled up the incline.&amp;nbsp;(b) Determine the initial speed of the second sled.

jlo2niT · Accepted Answer

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Jeffrey Jordon · Accepted Answer

a) Initial speed of sled 1 is u1=5.1 m/s  Final speed of sled 2 is vt=0  a=−gsin⁡θ  Then apply  V2−u2=2aS  V12−u12=−2gsin⁡θS  Here θ=35 then  0−u12=−2gsin⁡35×S  Then S=u122gsin⁡35=(5.1)22×9.8×0.5735  =2.314 m  b)Now Sled 1 and Sled 2 both reached the bottom at the same time then  Now S=12gsin⁡θt2  Then t=2Sgsin⁡θ  =2×2.3149.8×0.5735  =0.907 sec  Now Length of incline L=10 m  Then L=u2t+12(gsin⁡θ)t2  L=u2×0.907+2.314  10=u2×0.907+2.314  u2×0.907=10−2.314  u2×0.907=7.686  u2=8.4749 m/s

xleb123 · Accepted Answer

Answer:(a) The distance traveled by the first sled up the incline is 0 meters.(b) There is no valid solution for the initial speed of the second sled, v2.Explanation:(a) Distance traveled by the first sled:Let&#039;s denote the distance traveled by the first sled up the incline as d1.The potential energy at the bottom of the incline is converted into kinetic energy at the top, assuming no energy losses due to friction. Therefore, we can equate the potential energy at the bottom to the kinetic energy at the top:mgh=12mv12Here, m represents the mass of the sled, g is the acceleration due to gravity, and v1 is the speed of the first sled at the top of the incline.Since the sled momentarily stops at the point where it reaches, its kinetic energy becomes zero. Therefore, we can write:mgh=0From this equation, we find that the height h is zero, which means the sled did not travel up the incline at all. Hence, the distance traveled by the first sled, d1, is 0.(b) Initial speed of the second sled:Let&#039;s denote the initial speed of the second sled as v2.Since both sleds reach the bottom of the incline at the same moment, we can equate the time taken by the first sled to the time taken by the second sled:d1v1=10.0&amp;nbsp;mv2Substituting the value of d1 (which we found to be 0) and rearranging the equation, we get:0v1=10.0&amp;nbsp;mv2This equation simplifies to 0=10.0&amp;nbsp;m.Since the equation is not possible, there is no valid solution for the initial speed of the second sled, v2.

A frictionless plane is 10.0 m long and inclined atA sled starts at the bottom with an initial speed of 5.00 m/s up the incline. When it reaches the p

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