A 10.0 g marble slides to the left with a velocity ofmagnitude 0.300 m/s on thefrictionless, horizontal surface of an icy, New York sidewalk andhas a

BenoguigoliB

BenoguigoliB

Answered question

2021-02-20

A 10.0 g marble slides to the left with a velocity ofmagnitude 0.300 m/s on thefrictionless, horizontal surface of an icy, New York sidewalk andhas a head-on elastic collision with a larger 25.0 g marble sliding to the right with a velocityof magnitude 0.150 m/s (Fig. 8.35). 
(a) Find the velocity of each marble (magnitude anddirection) after the collision. (Since the collision is head-on,all the motion is along a line. Take right as the positivex direction.) 
m/s (smaller marble) 
m/s (larger marble) 
(b) Calculate the change in momentum (that is, the momentum afterthe collision minus the momentum before the collision) for eachmarble. 
kgm/s (smallermarble) 
kgm/s (largermarble) 
(c) Calculate the change in kinetic energy (that is, the kineticenergy after the collision minus the kinetic energy before thecollision) for each marble. 
J (smaller marble) 
J (larger marble)

Answer & Explanation

Talisha

Talisha

Skilled2021-02-21Added 93 answers

A. Mass of the first marble m1=25g
Initial velocity of the first marble u1=0.15m/s
Mass of the second marble m2=10g
Initial velocity of the second marble u2=0.3m/s
a) Then ν1=((m1m2)(m1+m2))u1+(2m2m1+m2u2)
ν2=(2m1m1+m2)u1+(m1m2m1+m2)u2
b) Initial momentum p1=m1u1+m2u2
final momentum p2=m1ν1+m2ν2
Change in momentum is the difference between the two momenta
c) Kinetic energy KE=12mν2
Find the total kinetic energy of the system before and after collisionand find the difference.

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