Boxes A and B are in contact on a horizontal, frictionless surface. Box A has mass 20.0 kg and box B has mass 5.0 kg. A horizontal force of 250 N is exerted on box A. What is the magnitude of the force that box A exerts on box B?

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Symbee · Accepted Answer

F=250 N is the force that causing acceleration for the entire system. By applying Newtons second law for the whole system, we can obtain the acceleration for the entire system: F=(mA+mB)ax ax=25020+5 ax=10 ms2 Box B accelerates due to the force (FA) exerted on it by box A. It accelereates at the same acceleration rate of the entire system (10 ms2) By applying Mewtons second law to box B: FA=mBax FA=5×10 =50 N Result: FA=50 N

Accepted Answer

F=250 N is the force that causing acceleration for the entire system.By applying Newtons second law for the whole system, we can obtain the acceleration for the entire system:F=(mA+mB)axax=25020+5ax=10&amp;nbsp;ms2Box B accelerates due to the force&amp;nbsp;(FA)&amp;nbsp;exerted by box A. It accelerates at the same acceleration rate of the entire system (10&amp;nbsp;ms2)By applying Newtons second law to box B:FB=mBaxFB=5×10=50&amp;nbsp;Ntherefore : the force that Box A exerted on box B is 50 N....&amp;nbsp;&amp;nbsp;*I just corrected the solution*&amp;nbsp;

Vasquez · Accepted Answer

Step 1:Let&#039;s denote the force exerted by box A on box B as FAB, and the force exerted by box B on box A as FBA. Since the two boxes are in contact, the magnitude of these forces will be the same.According to Newton&#039;s third law, we have:FAB=−FBAGiven that a horizontal force of 250 N is exerted on box A (FA=250 N), we need to determine the magnitude of FAB.Since box A and box B are in contact, they will move together with the same acceleration. We can use Newton&#039;s second law of motion to relate the force applied to box A to its acceleration.The equation for Newton&#039;s second law is:FA=mA·a where mA is the mass of box A and a is the acceleration of the boxes.Rearranging the equation, we have:a=FAmAStep 2:Substituting the given values, we have:a=250N20.0kgCalculating this expression, we find:a=12.5m/s2Since box B and box A have the same acceleration, we can write the equation for box B as:FB=mB·a where mB is the mass of box B.Substituting the given values, we have:FB=5.0kg·12.5m/s2Step 3:Calculating this expression, we find:FB=62.5NSince the force exerted by box A on box B (FAB) and the force exerted by box B on box A (FBA) are equal in magnitude but opposite in direction, we can conclude that the magnitude of the force that box A exerts on box B is 62.5 N. Therefore:FAB=62.5N

Don Sumner · Accepted Answer

To solve the problem, let&#039;s denote the force that box A exerts on box B as FAB. We can apply Newton&#039;s third law of motion, which states that the force exerted by box A on box B is equal in magnitude but opposite in direction to the force exerted by box B on box A.Since box A experiences a horizontal force of 250 N, we have FAB=−250 N. Here, the negative sign indicates that the force exerted by box A on box B is in the opposite direction to the applied force.

Boxes A and B are in contact on a horizontal, frictionless surface. Box A has ma

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