What is the magnitude of the net force on the first wire in (Figure 1)?What is the magnitude of the net force on the second wire in (Figure 1)?What is the magnitude of the net force on the third wire in (Figure 1)?photo

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Emmy Sparks · Accepted Answer

Step 1From the diagram, you can see that wire 1 has an attracting force from wire 3 at 0.04 m distance and a repelling force from wire 2 at 0.02 m distance.Expression of the force is  F  =  μ  ×      I    1    ×      I    2    ×      L          2      π      d      When   d  =  0.02  m ,  F  =            4      ×      π      ×              10                  −          7                    ×      10      ×      0.50              2      ×      π      ×      0.02        =  0.00025  NAnd when   d  =  0.04  m ,  F  =            4      π      ×              10                  −          7                    ×      10      ×      10      ×      0.50              2      π      ×      0.04        =  0.00025  Na) So, the net force on wire   1  =  0.005  −  0.00025  =  0.00025  N repelling, or upward.b) Wire 2 has equal repelling forces from wires 1 and 3, so net force   =  0c) By symmetry, the net force on wire 3 is the same means, 0.00025 N, but downward direction.

What is the magnitude of the net force on the

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