Earth has a magnetic dipole moment of 8.0 <mtext>&#xA0;</mtext> 10 <mrow class=

spazzter08dyk2n

spazzter08dyk2n

Answered question

2022-05-08

Earth has a magnetic dipole moment of 8.0   10 22   J / T. Find the magnitude of current in a single turn of wire extending around Earth at its geomagnetic equator to produce a dipole having the same dipole moment. Could such an arrangement be used to cancel out Earth's magnetism?

Answer & Explanation

notemilyu1208

notemilyu1208

Beginner2022-05-09Added 20 answers

a)The expression for the magnetic dipole moment is written as,
M = I A ( 1 )
Here, I and A represent the magnitude of current and the cross-section area of a loop, respectively.
Step 2
The cross-section area of a loop will be,
A = π r 2
Here, r represents the radius of the Earth.
The radius of the Earth is around 6370 km.
Therefore,
A = π ( 6370 × 10 3   m ) 2 = 1.274 × 10 14   m 2
Step 3
Substitute all the known values in the equation (1) to calculate the magnitude of current.
8 × 10 22   J / T = I ( 1.274 × 10 14   m 2 ) I = 6.3 × 10 8   A
Alissa Hutchinson

Alissa Hutchinson

Beginner2022-05-10Added 5 answers

b)Yes, at a far distance from the loop, the loop behaves as a dipole. So, the magnetic field due to the loop and earth produces a dipole field. Therefore, they cancel out each other.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Electromagnetism

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?