Consider a region where a 35-volt-per-meter electric field and a 20-millitesla magnetic field both e

Jazlyn Raymond

Jazlyn Raymond

Answered question

2022-04-12

Consider a region where a 35-volt-per-meter electric field and a 20-millitesla magnetic field both exists and are perpendicular to each other. If a proton is moving at a speed of 2 km/s and the magnitude of the force it experiences is 8 × 10 18 newtons, determine the direction of the movement of the proton relative to the direction lying on the same plane. the magnetic field. Assume the electric field, magnetic field, and the velocity vector are all
a.) 47.13 degrees with respect to the magnetic field;
b.) 63.21 degrees with respect to the magnetic field;
c.) 87.20 degrees with respect to the magnetic field;
d.) 21.90 degrees with respect to the magnetic field;

Answer & Explanation

ele5ph1a7jl1

ele5ph1a7jl1

Beginner2022-04-13Added 21 answers

Step 1
Given data:
E=35 V/m
B=20 mT
v=2 km/s
F = 8 × 10 18   N
Step 2
The charge on the proton is given as,
q = F E = 8 × 10 18 35 C
The formula for force on proton is given as,
F = q v B sin θ 8 × 10 18 = 8 × 10 18 35 × 2 × 10 3 × 20 × 10 3 × sin θ θ = 61.04

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