delta I=delta Q/delta t=J*delta s. My understanding is that delta can be replaced by d which represents the differential(infinitesimally small amount) of (something).

Rosemary Burns

Rosemary Burns

Open question

2022-08-21

Δ I = Δ Q / Δ t = J Δ s \Delta I= \Delta Q / \Delta t = \vec J \cdot \Delta \vec s
My understanding is that Δ \Delta can be replaced by d d which represents the differential(infinitesimally small amount) of (something). Thus, this equation becomes d I = d Q / d t = J d s dI=dQ/dt=\vec J \cdot d \vec s . We integrate both sides and get I = J d s = d Q / d t I=\int \vec J \cdot d\vec s=\int dQ/dt . But I know that I = d Q / d t I=-dQ/dt not d Q / d t \int dQ/dt . Can someone clear this confusion with the deltas and the differentials.

Answer & Explanation

blerbintiy0

blerbintiy0

Beginner2022-08-22Added 8 answers

The first equation, Δ I = Δ Q / Δ t \Delta I= \Delta Q / \Delta t , should be I = Δ Q / Δ t I= \Delta Q / \Delta t . The current is the amount of charge flowing per unit time. I'm not sure what the Δ \Delta in Δ I \Delta I is doing there at all, but it seems to be an error.

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