A particle with a charge of 5 mu C is moving at 3 * 10^6 m/s perpendicularly through a magnetic field with a strength of 0.06T. What is the magnitude of the force on the particle?

clovnerie0q

clovnerie0q

Answered question

2022-10-02

A particle with a charge of 5 μ C is moving at 3 10 6   m / s perpendicularly through a magnetic field with a strength of 0.06T. What is the magnitude of the force on the particle?

Answer & Explanation

Salma Baird

Salma Baird

Beginner2022-10-03Added 8 answers

Charge of the particle (q) = 5 × 10 6   C
Velocity of the particle (v) = 3 × 10 6   m / s
Magnetic field ( B ) = 0.06 T
Magnitude of force
F = q ( v × B ) F = q v B sin 90 0 F = 5 × 10 6 × 3 × 10 6 × 0.06 F = 0.9   N e w t o n
So,magnitude of force = 0.9 Newton

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Electromagnetism

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?