The magnetic flux density within a bar of some material is 0.630 tesla at an H field of 5 xx 10^5 A/m. Compute the following for this material: (a) the magnetic permeability, and (b) the magnetic susceptibility. (c) What type(s) of magnetism would you suggest is(are) being displayed by this material ? Why ?

Karley Castillo

Karley Castillo

Answered question

2022-11-14

The magnetic flux density within a bar of some material is 0.630 tesla at an H field of 5 × 10 5   A / m. Compute the following for this material: (a) the magnetic permeability, and (b) the magnetic susceptibility. (c) What type(s) of magnetism would you suggest is(are) being displayed by this material ? Why ?

Answer & Explanation

hocelwsmjc

hocelwsmjc

Beginner2022-11-15Added 16 answers

Magnetic permeability
μ = B H
Where, B=magnetic flux density=0.63 T
H=intensity of magnetic field = 5 × 10 5 A m
μ = 0.63   T 5 × 10 5   A m = 0.126 × 10 5   N A 2
Find magnetic susceptibility χ:
B = μ H ( 1 + χ ) χ = B μ H 1 = 0.63   T 5 × 10 5   A m 1 × 0.126 × 10 5   H m 1 1 = 0
Magnetic susceptibility explains how the spins in a material will align themselves when magnetized.
If material aligns in the direction of applied magnetic field, χ > 0, the material is paramagnetic.
If material aligns against the direction of applied magnetic field, χ < 0, the material is diamagnetic.
In this problem, χ = 0 implies the material do not respond to the applied magnetic field. Thus the material is neither paramagnetic nor diamagnetic in nature.
Or the material might be a very weak paramagnetic or very weak diamagnetic in nature (because its susceptibility might be approaching zero).

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Electromagnetism

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?