How to find all points having an x coordinate of 3 whose distance from the point (-1, -4) is 5?

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Mikayla Cox · Accepted Answer

The following formula is used to determine the separation between two points:d=(x2−x1)2+(y2−y1)2We can let You can&#039;t use &#039;macro parameter character #&#039; in math modeYou can&#039;t use &#039;macro parameter character #&#039; in math modeWe can let You can&#039;t use &#039;macro parameter character #&#039; in math modeYou can&#039;t use &#039;macro parameter character #&#039; in math mode Substituting these values and 5 for d, we can solve for y1:5=(−1−3)2+(−4−y1)2First, square both sides of the equation:52=((−1−3)2+(−4−y1)2)225=(−1−3)2+(−4−y1)225=(−4)2+(−4−y1)225=16+(−4−y1)225=16+((−4)2−(2⋅−4⋅y1)+y12)25=16+(16−(−8y1)+y12)25=16+16+8y1+y1225=32+8y1+y1225=y12+8y1+3225−25=y12+8y1+32−250=y12+8y1+7y12+8y1+7=0This can be considered as:(y1+7)(y1+1)=0Now that we have found the solutions, we can solve each term on the left for 0:Solution 1:y1+7=0y1+7−7=0−7y1+0=−7y1=−7Solution 2:y1+1=0y1+1−1=0−1y1+0=−1y1=−1The two points satisfying this problem are:(3,−7) and (3,−1)

How to find all points having an x coordinate of 3 whose distance from the point (-1, -4) is 5?

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