Evaluate this indefinite integral: ∫(3x+5)dx

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escumantsu · Accepted Answer

The value of indefinite integration must be determined in this case. We are aware that indefinite integrals are those integrals without an upper or lower bound.
Here we use the formula of integration $\int x^{n} d x = \frac{x^{n + 1}}{n + 1} + C$
And we know that $\int k d x = k (x) + C$
Consider the indefinite integral $\int (3 x + 5) d x$ .
We can integrate the above expression using the formula $\int x^{n} d x = \frac{x^{n + 1}}{n + 1} + C$ . Here we have $(3 x^{1} + 5)$
thus we have n=1.
Integrating the above expression , we get
$\int (3 x + 5) d x = 3 \int x d x + 5 \int d x$
$= 3 (\frac{x^{1 + 1}}{1 + 1}) + 5 x$
$= \frac{3 x^{2}}{2} + 5 x + C$
hence we have $\int (3 x + 5) d x = \frac{3 x^{2}}{2} + 5 x + C$ .

Evaluate this indefinite integral: (3x+5)dx

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