Use the table of values of f(x,y) to estimate the values of fx(3,2), fx(3,2.2), and fxy(3,2). y1.82.02.2x2.512.510.29.33.018.117.515.93.520.022.426.1

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Use the table of values of f(x,y) to estimate the values of fx(3,2), fx(3,2.2), and fxy(3,2).  y1.82.02.2x2.512.510.29.33.018.117.515.93.520.022.426.1

au4gsf · Accepted Answer

Step 1 fx(3.2)=(f(3.5, 2)−f(2.5, 5))(3.5−2.5) =(22.4−10.2)1.0 =12.21.0 =12.2 fx(3, 2.2)=(f(3.5, 2.2)−f(2.5, 2.2))(3.5−2.5) =26.1−9.3)1=16.8 For fxy(3,2), we have choices. If we don&#039;t care about centering the y, we can use the results already gathered here. Then, fxy(3.2)=(fx(3, 2.2)−fx(3.2))(2.2−2) =(16.8−12.2)2=23 If we had wanted to center it, we could have used (f(3.5, 2.2)−f(3.5, 1.8)−f(2.5, 2.2)+f(2.5, 1.8))((2.2−1.8)⋅(3.5−2.5) =(26.1−20−9.3+12.5)(4⋅1)=23.25

Jeffrey Jordon · Accepted Answer

We need to estimate the values of fx(3,2), fx(3,2.2), and fxy(3,2)  We have f(3, 2) = 17.5 and f(3, 2.2) = 15.9.  For fx(3,2):  fx(3,2)=22.4−17.53.5−3=9.8.  For fx(3,2.2)  fx(3,2.2)=26−15.93.5−3=20.2  Again,  For fxy(3,2)  We know that fxy(3,2)=(fx(3,2))y=fx(3,2.2)−fx(3,2)2.2−2   =20.2−9.80.2  = 52

Use the table of values of f(x, y) to estimate the values of fx(3, 2), fx(3, 2.2), and fxy(3, 2). \begin{array}{|c|c|}\hline y & 1.8 & 2.0 & 2.2 \\ \hline x & & & \\ \hline 2.5 & 12.5 & 10.2 & 9.3 \\ \hline 3.0 & 18.1 & 17.5 & 15.9 \\ \hline 3.5 & 20.0 & 22.4 & 26.1 \\ \hline \end{array}

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