To make: A true statement by inserting a symbol &lt;, &gt; or = between the given numbers 0.6―and56.

The given numbers are 0.6¯ and 56. To compare the numbers 0.6―and56, first we write the fraction 56 as decimal and compare with the decimal 0.6¯. 60.8335.00 −4820 −1820 −1820 −182 Thus, 56=0.833…or0.83―. Now, we compare this with given decimal 0.6¯. Original number 0.6―56 Decimals0.6―0.83― Compare 0.6―&lt;0.83― Thus, 0.6―&lt;56. Final statement: 0.6―&lt;56.

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melodykap

Answered question

2021-01-15

To make: A true statement by inserting a symbol

<, > o r = between the given numbers \overset{―}{0.6} and \frac{5}{6} .

Answer & Explanation

Alannej

Skilled2021-01-16Added 104 answers

The given numbers are $\bar{0.6} a n d \frac{5}{6} .$
To compare the numbers $\overset{―}{0.6} and \frac{5}{6}, first we write the fraction \frac{5}{6} as decimal and compare with the decimal \bar{0.6} .$
$6 \frac{0.833}{5.00}$
$\frac{- 48}{20}$
$\frac{- 18}{20}$
$\frac{- 18}{20}$
$\frac{- 18}{2}$
Thus, $\frac{5}{6} = 0.833 \dots or \overset{―}{0.83} .$
Now, we compare this with given decimal $\bar{0.6} .$
Original number $\overset{―}{0.6} \frac{5}{6}$
Decimals $\overset{―}{0.6} \overset{―}{0.83}$
Compare $\overset{―}{0.6} < \overset{―}{0.83}$
Thus, $\overset{―}{0.6} < \frac{5}{6} .$
Final statement:
$\overset{―}{0.6} < \frac{5}{6} .$

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