Alyce Wilkinson

2021-01-22

Find the rationalize the denominator of $\frac{-4}{\sqrt[3]{5x}}$

pierretteA

Skilled2021-01-23Added 102 answers

Rationalize the denominator is given by

$\frac{-4}{\sqrt[3]{5x}}=\frac{-4}{(5x{)}^{\frac{1}{3}}}$

$=\frac{-4}{\frac{(5x{)}^{1}}{3}}\text{}\times \text{}\frac{\frac{(5x{)}^{2}}{3}}{(5x{)}^{\frac{2}{3}}}$

$=\frac{-a(5x{)}^{\frac{2}{3}}}{(5x{)}^{\frac{1}{3}\text{}+\text{}\frac{1}{2}}}$

$=\frac{-4((5x{)}^{\frac{2}{3}})}{(5x{)}^{\frac{2}{2}}}$

$=\frac{-4(5x{)}^{\frac{2}{3}}}{5x}$

Jeffrey Jordon

Expert2021-11-03Added 2605 answers

Answer is given below (on video)

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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