Evaluate the following integrals. \int10\tan^9x\sec^2xdx

hexacordoK

hexacordoK

Answered question

2021-10-21

Evaluate the following integrals.
10tan9xsec2xdx

Answer & Explanation

joshyoung05M

joshyoung05M

Skilled2021-10-22Added 97 answers

To determine
to determine:
10tan9xsec2xdx
Calculation
Let tanx=u
sec2xdx=du
So, the integral becomes
10tan9xsec2xdx=10u9du
10tan9xsec2xdx=10u1010+C
10tan9xsec2xdx=10u9+19+1+C
10tan9xsec2xdx=10u1010+C
10tan9xsec2xdx=u10+C
10tan9xsec2xdx=(tanx)10+C

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