"Evaluate the integrals ∫−π30sec⁡xtan⁡xdx" solved and explained

emancipezN

Answered question

2021-10-14

Evaluate the integrals

\int_{- \frac{π}{3}}^{0} \sec x \tan x d x

Laith Petty

Skilled2021-10-15Added 103 answers

Given information:

\int_{- \frac{π}{3}}^{0} \sec x \tan x d x

Formula:

\sec x \tan x d x = \sec x

Calculation:
Write the define integral.

\int_{\frac{- π}{3}}^{0} \sec x \tan x d x = {[\sec x]}_{\frac{- π}{3}}^{0}

= \sec 0 - \sec (\frac{- π}{3})

= 1 - 2

= - 1

Therefore, the value of the definite integral

\int_{- \frac{π}{3}}^{0} \sec x \tan x d x

is -1

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