Evaluate the following integrals. \int\frac{dx}{\sqrt{36x^2-25}},x>5/6

Lennie Carroll

Lennie Carroll

Answered question

2021-10-08

Evaluate the following integrals.
dx36x225,x>56

Answer & Explanation

Liyana Mansell

Liyana Mansell

Skilled2021-10-09Added 97 answers

Let,
z=6x
dz=6dx
dx=dz6 Then we integrate by substitutiion
dx36x225
=1z225dx6
=161z225dz
=16ln(z+z225)+C
=16ln(6x+36x225)+C
Answer: 16ln(6x+36x225)+C

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?