Evaluate the integral. \int \frac{ax}{x^{2}-bx}dx

Harlen Pritchard

Harlen Pritchard

Answered question

2021-11-05

Evaluate the integral.
axx2bxdx

Answer & Explanation

Dora

Dora

Skilled2021-11-06Added 98 answers

Step 1
The given integral (axx2bx)dx can be evaluated as,
(axx2bx)dx=(axx(xb))dx
=(axb)dx
Put, x-b=t
Taking differential on both sides,
dx=dt
Step 2
So, the (axb)dx becomes,
atdt=adtt
=a(log|t|+C)
Replace t by x−b,
(axx2bx)dx=a(log|xb|+C)
Hence, (axx2bx)dx=a(log|xb|+C).

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