Find the indefinite integral and check the result by differentiation.

pedzenekO

pedzenekO

Answered question

2021-11-07

Find the indefinite integral and check the result by differentiation.
(23x10)dx

Answer & Explanation

Alara Mccarthy

Alara Mccarthy

Skilled2021-11-08Added 85 answers

Step 1
Consider the provided integral,
(23x10)dx
Find the indefinite integral and check the result by differentiation.
So,
(23x10)dx=2dx3x10dx
Step 2
Therefore,
2dx=2x+C1
3x10dx=3x10+110+1+C213x9+C2
Let C=C1C2. Now, find the indefinite integral.
(23x10)dx=2dx3x10dx
=2x+C1+13x9C2
=2x+13x9+C
Step 3
Now, differentiate the above 2x+13x9+C.
So,
ddx(2x+13x9+C)=ddx(2x)+ddx(13x9)+ddx(C)
=2+9x9+13+0
=23x10
=23x10
Hence, (23x10)dx.

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