Evaluate the integral. \int \frac{dx}{8-x^{2}}, x>2\sqrt{2}

deliredejoker7m

deliredejoker7m

Answered question

2021-11-06

Evaluate the integral.
dx8x2,x>22

Answer & Explanation

Provere

Provere

Beginner2021-11-07Added 18 answers

Step 1
Given:
18x2dx
evaluate.
Step 2
Evaluating;
Take x=22t.
18x2dx=122(t2+1)dt
=1221t2+1du
Take x=22t.
18x2dx=122(t2+1)dt
=1221t2+1du
=122(ln|t+1|2ln|t1|2)
=142(ln|x22+1|ln|x221|)+c

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