Get the answer to "Evaluate the indefinite integral: ∫(18t5−10t4−28t)dt"

ofodse

Answered question

2021-11-20

Evaluate the indefinite integral:

\int (18 t^{5} - 10 t^{4} - 28 t) d t

Drood1980

Beginner2021-11-21Added 16 answers

Step 1
Given the indefinite integral:

\int (18 t^{5} - 10 t^{4} - 28 t) d t

Step 2
We know that

\int x^{n} d x = \frac{x^{n + 1}}{n + 1} + c

Where c is integrating constant.

\int (18 t^{5} - 10 t^{4} - 28 t) d t = \frac{18 t^{5 + 1}}{5 + 1} - \frac{10 t^{4 + 1}}{4 + 1} - \frac{28 t^{1 + 1}}{1 + 1} + c

\int (18 t^{5} - 10 t^{4} - 28 t) d t = \frac{18 t^{6}}{6} - \frac{10 t^{5}}{5} - \frac{28 t^{2}}{2} + c

\int (18 t^{5} - 10 t^{4} - 28 t) d t = 3 t^{6} - 2 t^{5} - 14 t^{2} + c

Prioned

Beginner2021-11-22Added 11 answers

Step 1: Expand.

\int 18 t^{5} - 10 t^{4} - 28 t d t

Step 2: Use Power Rule:

\int x^{n} d x = \frac{x^{n + 1}}{n + 1} + C

3 t^{6} - 2 t^{5} - 14 t^{2}

Step 3: Add constant.

3 t^{6} - 2 t^{5} - 14 t^{2} + C

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