\int_{0}^{6}|2x-4|dx

uneskovogl5

uneskovogl5

Answered question

2021-12-05

06|2x4|dx

Answer & Explanation

Mary Moen

Mary Moen

Beginner2021-12-06Added 14 answers

2x-4>0 for x>2
so for 0<x<2 |2x-4|=-2x+4
so, I= int from x=0 to 2(4-2x)+ integ from x=2 to 6 (2x-4)
=(4xx2) from 0 to 2+(x24x) from 2 to 6
=(8-4-0)+(36-24-(4-4*2))
=4+12+4=20

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