How do you find the eccentricity, directrix, focus and classify

kaibaloveyou3cj

kaibaloveyou3cj

Answered question

2022-02-12

How do you find the eccentricity, directrix, focus and classify the conic section r=0.810.8sinθ?

Answer & Explanation

deliria1t4

deliria1t4

Beginner2022-02-13Added 13 answers

It is a typical equation of an ellipse in polar form. However, it is easier to identify conic section, its eccentricity, directrix and focus in rectangular coordinates. Hence, let us convert the polar equation in rectangular form.
The relation between polar form (r,θ) and rectangular form (x, y) is given by x=rcosθ and y=rsinθi.e. r2=x2+y2.
Hence r=0.810.8sinθ can be written as
r45rsinθ=45 or 5r4rsinθ=4
or 5x2+y24y=4
or 25x2+25y2=(4+4y)2=16y2+32y+16
or 25x2+9y232y16=0
or 25x2+9(y22×169y+(169)2)256916=0
or 25x2+9(y169)2=4009
or x24009×25+(y169)24009×9=1
or x2(43)2+(y169)2(209)2=1
Hence, this is the equation of an ellipse of the form (xh)2a2+(yk)2b2=1, whose center is (0,169), major axis parallel to y-axis is 2×209=409 and minor axis parallel to x-axis is 2×43=83
eccentricity is given by e=1a2b2

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