The conclusion about the values of e for rlliptical equations. The provided equations of conic sections are, A) x236 − y213=1 B) x24 − y24=1 C) x225 − y216=1 D) x225 − y239=1 E) x217 − y281=1 F) x236 − y236=1 G) x216 − y265=1 H) x2144 − y2140=1

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The conclusion about the values of e for rlliptical equations. The provided equations of conic sections are,  A) x236 − y213=1  B) x24 − y24=1  C) x225 − y216=1  D) x225 − y239=1  E) x217 − y281=1  F) x236 − y236=1  G) x216 − y265=1  H) x2144 − y2140=1

Clara Reese · Accepted Answer

Concept used: The general equation of an ellipse with center (0, 0) is, x2a2 + y2b2=1. The value of e for the above equation is e= cd Consider the equations of conic sections,  A) x236 − y213=1  B) x24 − y24=1  C) x225 − y216=1  D) x225 − y239=1  E) x217 − y281=1  F) x236 − y236=1  G) x216 − y265=1  H) x2144 − y2140=1  On comparing the above equations with the general form of an ellipse, the elliptical equations are (C), (E) and (H). The value of eccentricity e for the conic section of the equation x225 + y216=1 is e=0.6. The value of eccentricity e for the conic section of the equation x217 + y281=1 is e=0.89. The value of eccentricity e for the conic section of the equation x2144 + y2140=1 is e=0.33. Therefore, the value of e for elliptical equations lies between 0 and 1 i.e. 0 &amp;lt; e &amp;lt; 1.

The conclusion about the values of e for rlliptical equations. The provided equations of conic sections are, A) frac{x^{2}}{36} - frac{y^{2}}{13}=1 B)

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