The problem is to prove that: \(\displaystyle{\int_{{-\pi}}^{{\pi}}}{\int_{{-\pi}}^{{\pi}}}{\left({a}{\sin{{\left({x}\right)}}}+{b}{\cos{{\left({x}\right)}}}+{c}{\sin{{\left({y}\right)}}}+{d}{\cos{{\left({y}\right)}}}\right)}{e}^{{-{2}{\cos{{\left({y}-{x}\right)}}}+{a}{\cos{{\left({x}\right)}}}-{b}{\sin{{\left({x}\right)}}}+{c}{\cos{{\left({y}\right)}}}-{d}{\sin{{\left({y}\right)}}}}}{\left.{d}{x}\right.}{\left.{d}{y}\right.}\) I have

Ormezzani6cuu

Ormezzani6cuu

Answered question

2022-04-11

The problem is to prove that:
ππππ(asin(x)+bcos(x)+csin(y)+dcos(y))e2cos(yx)+acos(x)bsin(x)+ccos(y)dsin(y)dxdy
I have an idea to represent a function under the integral like the odd function, but I can't.
Also, I can prove, that: ππ(acos(x)+bsin(x))easin(x)bcos(x)dx=0

Answer & Explanation

blogspainmarax6qi

blogspainmarax6qi

Beginner2022-04-12Added 12 answers

Writing e(x,y)=e2cos(xy)+acosxbsin(x)+ccosydsiny
ππππ(asin(x)+bcos(x)+csin(y)+dcos(y))e(x,y)dxdy=ππππ(x+y)e(x,y)dxdy
The result follows

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