Evaluate ∫ − 1 t 2 + t − 1 d t.

Multiply&nbsp;1t2+t-1&nbsp;by&nbsp;t2+t-1t2+t-1.-(1t2+t-1⋅t2+t-1t2+t-1)Combine and simplify the denominator.-t2+t-1t2+t-1&nbsp;

Key to "Evaluate ∫ − 1 t 2 + t..."

Blaine Stein

2022-05-12

Evaluate

\int - \frac{1}{\sqrt{t^{2} + t - 1}} ﻿ d t

Finnegan Zimmerman

Beginner2022-05-13Added 16 answers

Multiply $\frac{1}{\sqrt{t^{2} + t - 1}}$ by $\frac{\sqrt{t^{2} + t - 1}}{\sqrt{t^{2} + t - 1}}$ .

$- (\frac{1}{\sqrt{t^{2} + t - 1}} \cdot \frac{\sqrt{t^{2} + t - 1}}{\sqrt{t^{2} + t - 1}})$

Combine and simplify the denominator.

$- \frac{\sqrt{t^{2} + t - 1}}{t^{2} + t - 1}$

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