We have f:R rightarrow R,f(x)=x^2+x sin (x), and we need to find intervals of monotonicity.

targetepd

targetepd

Answered question

2022-08-10

Find the rate of change of main dependent variable
We have f : R R , f ( x ) = x 2 + x sin ( x ), and we need to find intervals of monotonicity. Here is all my steps:
f ( x ) = 2 x + x cos ( x ) + sin ( x )
f ( x ) = 0 x = 0 the only solution.
Now I need to find where f′ is positive and negative. I don't want to put value for f′ to find the sign, I want another method. So I tried to differentiate the function again to see if f′ is increasing or decreasing:
f ( x ) = 2 x sin ( x ) + cos ( x ), but I don't know if f ( x ) 0 or f ( x ) 0.
How can I find the sign for f′ to determine monotony of f ?

Answer & Explanation

Kelton Glover

Kelton Glover

Beginner2022-08-11Added 17 answers

Step 1
You know that the function f′(x) is a continuous function with only one root. This means that the sign of the function is the same on [ 0 , ), and this means that no matter what value of x > 0 you take, you will find the sign of f′(x) on this interval.
In some cases, it's good to take a particular value since that makes it easier. In your case, it's very easy to calculate f ( 2 π ) ,, for example.
Also, you can try to see what the limit of f′(x) is when x becomes large. If the limit is positive (or if it is ), then the sign of f′ is also positive on [ 0 , ). In your case, the limit is easy to calculate.

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