Sarah can paddle a rowboat at 6 m/s in still water. She heads out across a 400 m river at an angle of 30 upstream. She reaches the other bank of the river 200 m downstream from the direct opposite point from where she started. Determine the river current?

dimenjaurfb

dimenjaurfb

Answered question

2023-02-02

Sarah can paddle a rowboat at 6 m/s in still water. She heads out across a 400 m river at an angle of 30 upstream. She reaches the other bank of the river 200 m downstream from the direct opposite point from where she started. Determine the river current?

Answer & Explanation

Menziani8o2

Menziani8o2

Beginner2023-02-03Added 8 answers

Let us consider this as a projectile problem where there is no acceleration.
Let v R be river current. Sarah's motion has two components.
Across the river.
Along the river.
Both can be handled separately because they are orthogonal to one another.
Given is width of river = 400   m
200 meters downstream from the opposite point of start is the place of landing on the other bank.
We know that time taken to paddle directly across must be equal to time taken to travel 200   m downstream parallel to the current. Let it be equal to t
Setting up equation across the river
( 6 cos 30 ) t = 400
t = 400 6 cos 30 ......(1)
She paddles upstream with the current in equation
( v R - 6 sin 30 ) t = 200 .....(2)
Using (1) to rewrite (2) we get
( v R - 6 sin 30 ) × 400 6 cos 30 = 200
v R = 200 400 × ( 6 cos 30 ) + 6 sin 30
v R = 2.6 + 3
v R = 5.6   m s - 1

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Linear algebra

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?