The position vector r(t)=⟨ln t,1t2,t4⟩ describes the path of an object moving in space. (a) Find the velocity vector, speed, and acceleration vector of the object. (b) Evaluate the velocity vector and acceleration vector of the object at the given value of t=3

Question

The position vector r(t)=⟨ln t,1t2,t4⟩ describes the path of an object moving in space. (a) Find the velocity vector, speed, and acceleration vector of the object. (b) Evaluate the velocity vector and acceleration vector of the object at the given value of t=3

komunidadO · Accepted Answer

a) Velocity vector is the derivative of position vector. So to find velocity vector, differentiate position vector with respect to t. We get v(t)=⟨15,−2t3,4t3⟩ Now speed is the magnitude of velocity vector. That is, Speed =||v|| =(1t)2+(−2t3)2+(4t3)2 =1t2+4t6+16t6 =t4+4+16t12t6 =(16t12+t4+4)t3 Acceleration vector is the derivative of the velocity vector. So to find acceleration vector, differentiate velocity vector with respect to t. We get, a(t)=⟨−1t2, −2(−3t4), 4(3t2)⟩  =⟨−1t2, 6t4, 12t2⟩ b) Put t=3 in the velocity vector, we get v(3)=⟨13,−2(3)3,4(3)3⟩ =⟨13,−233,123⟩ Put t=3 in the acceleration vector, we get a(3)=⟨−1(3)2,6(3)4,12(3)2⟩ =⟨−13,69,12(3)⟩ =⟨−13,23,36⟩

The position vector r(t) =<<n t, 1/ t^2, t^4>> describes the path of an object moving in space. (a) Find the velocity vector, speed, and acceleration vector of the object. (b) Evaluate the velocity vector and acceleration vector of the object at the given value of t = sqrt3

Answered question

Answer & Explanation

New Questions in Linear algebra