The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution,

jernplate8

jernplate8

Answered question

2021-06-14

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent. [101|1012|1]

Answer & Explanation

Benedict

Benedict

Skilled2021-06-15Added 108 answers

There are no impossible equations, such as (0=1), the system is consistent,
A variable does not have a leading 1 in its corresponding column, so we take it asa parameter ... the system is consistent and has infinitely many solution.
Parameters: x3R
Interpreting row by row as equations.

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