The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution,

Chesley

Chesley

Answered question

2021-05-03

The reduced row echelon form of the augmented matrix of a system of linear equations is given. Tell whether the system has one solution, no solution, or infinitely many solutions. Write the solutions or, if there is no solution, say the system is inconsistent. [1200|40010|30001|20000|0]

Answer & Explanation

Bella

Bella

Skilled2021-05-04Added 81 answers

There are no impossible equations, such as (0=1), the system is consistent,
One variables does not have a leading 1 in its corresponding column, so we take it as a parameter ... the system is consistent and has infinitely many solutions.
Parameters: x2R
Interpreting row by row as equations.

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