Consider the following system \begin{cases}y=30-x\\2y=-x^{2}+16x-12\end{cases}

pancha3

pancha3

Answered question

2021-08-10

Consider the following system.
{y=30x2y=x2+16x12

Answer & Explanation

2k1enyvp

2k1enyvp

Skilled2021-08-11Added 94 answers

y=30x(1)
2y=x2+16x12(2)
from 1 and 2 we have
2(30x)=x2+16x12
602x=x2+16x12
x216x2x+12+60=0
x218x+72=0
x26x12x+72=0
x(x6)12(x6)=0
(x6)(x12)=0
x6=0,x12=0
x=6,x=12
when x=6,y=306=24[om1]
when x=12,y=3012=18[om1]
Hence the requined solution
(6,24) and (12,18)

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Linear algebra

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?