Solve the system by back substitution. Assume that the variables are named x1,x2,…from left to right. [1,0,0.0,1,0.5,-2,1.3,4,1.2,-7,3]

vazelinahS

vazelinahS

Answered question

2021-09-25

Suppose that the augmented matrix for a system of linear equations has been reduced by row operations to the given row echelon form. Solve the system by back substitution. Assume that the variables are named x1,x2,from left to right. [105320124700113]

Answer & Explanation

Talisha

Talisha

Skilled2021-09-26Added 93 answers

The linear system corresponding to the augmented matrix is
x1+5x3+3x4=2
x22x3+4x4=7
x3+x4=3
Solve for the leading variables. x1=25x33x4
x2=7+2x34x4
x3=3x4
Substitute x3=3x4 into the first two equations.
x1=13+2x4
x2=16x4
x3=3x4
Assign arbitrary value to free variable x4, say x4=t. Then the solution is described by the parametric equations. x1=13+2t,x2=16t,x3=3t,x4=t

Jeffrey Jordon

Jeffrey Jordon

Expert2021-10-12Added 2605 answers

Answer is given below (on video)

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